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[v12,02/21] PCI: Print PF SR-IOV resource that contains all VF(n) BAR space

Message ID 20150224083309.32124.29690.stgit@bhelgaas-glaptop2.roam.corp.google.com (mailing list archive)
State Accepted
Commit e88ae01d2c43be3c3a6f340bfa7bab8b87127f57
Headers show

Commit Message

Bjorn Helgaas Feb. 24, 2015, 8:33 a.m. UTC
From: Wei Yang <weiyang@linux.vnet.ibm.com>

When we size VF BAR0, VF BAR1, etc., from the SR-IOV Capability of a PF, we
learn the alignment requirement and amount of space consumed by a single
VF.  But when VFs are enabled, *each* of the NumVFs consumes that amount of
space, so the total size of the PF resource is "VF BAR size * NumVFs".

Add a printk of the total space consumed by the VFs corresponding to what
we already do for normal non-IOV BARs.

No functional change; new message only.

[bhelgaas: split out into its own patch]
Signed-off-by: Wei Yang <weiyang@linux.vnet.ibm.com>
Signed-off-by: Bjorn Helgaas <bhelgaas@google.com>
---
 drivers/pci/iov.c |    2 ++
 1 file changed, 2 insertions(+)
diff mbox

Patch

diff --git a/drivers/pci/iov.c b/drivers/pci/iov.c
index c4c33ead03bc..05f9d97e4175 100644
--- a/drivers/pci/iov.c
+++ b/drivers/pci/iov.c
@@ -372,6 +372,8 @@  found:
 			goto failed;
 		}
 		res->end = res->start + resource_size(res) * total - 1;
+		dev_info(&dev->dev, "VF(n) BAR%d space: %pR (contains BAR%d for %d VFs)\n",
+			 i, res, i, total);
 		nres++;
 	}