@@ -42,6 +42,7 @@ extern void __init lmb_init(void);
extern void __init lmb_analyze(void);
extern long lmb_add(u64 base, u64 size);
extern long lmb_remove(u64 base, u64 size);
+extern long __init lmb_free(u64 base, u64 size);
extern long __init lmb_reserve(u64 base, u64 size);
extern u64 __init lmb_alloc_nid(u64 size, u64 align, int nid,
u64 (*nid_range)(u64, u64, int *));
@@ -205,9 +205,8 @@ long lmb_add(u64 base, u64 size)
}
-long lmb_remove(u64 base, u64 size)
+static long __lmb_remove(struct lmb_region *rgn, u64 base, u64 size)
{
- struct lmb_region *rgn = &(lmb.memory);
u64 rgnbegin, rgnend;
u64 end = base + size;
int i;
@@ -254,6 +253,16 @@ long lmb_remove(u64 base, u64 size)
return lmb_add_region(rgn, end, rgnend - end);
}
+long lmb_remove(u64 base, u64 size)
+{
+ return __lmb_remove(&(lmb.memory), base, size);
+}
+
+long __init lmb_free(u64 base, u64 size)
+{
+ return __lmb_remove(&(lmb.reserved), base, size);
+}
+
long __init lmb_reserve(u64 base, u64 size)
{
struct lmb_region *_rgn = &lmb.reserved;
We can free memory allocated with lmb_alloc() by removing it from the list of reserved LMBs. Rework lmb_remove() to allow that possibility and add lmb_free() which exploits it. Signed-off-by: Michael Ellerman <michael@ellerman.id.au> --- include/linux/lmb.h | 1 + lib/lmb.c | 13 +++++++++++-- 2 files changed, 12 insertions(+), 2 deletions(-)