@@ -18846,24 +18846,17 @@ build_non_dependent_expr (tree expr)
TREE_OPERAND (expr, 0),
build_non_dependent_expr (TREE_OPERAND (expr, 1)));
+ /* Keep dereferences outside the NON_DEPENDENT_EXPR so lvalue_kind
+ doesn't need to look inside. */
+ if (TREE_CODE (expr) == INDIRECT_REF && REFERENCE_REF_P (expr))
+ return convert_from_reference (build_non_dependent_expr
+ (TREE_OPERAND (expr, 0)));
+
/* If the type is unknown, it can't really be non-dependent */
gcc_assert (TREE_TYPE (expr) != unknown_type_node);
- /* Otherwise, build a NON_DEPENDENT_EXPR.
-
- REFERENCE_TYPEs are not stripped for expressions in templates
- because doing so would play havoc with mangling. Consider, for
- example:
-
- template <typename T> void f<T& g>() { g(); }
-
- In the body of "f", the expression for "g" will have
- REFERENCE_TYPE, even though the standard says that it should
- not. The reason is that we must preserve the syntactic form of
- the expression so that mangling (say) "f<g>" inside the body of
- "f" works out correctly. Therefore, the REFERENCE_TYPE is
- stripped here. */
- return build1 (NON_DEPENDENT_EXPR, non_reference (TREE_TYPE (expr)), expr);
+ /* Otherwise, build a NON_DEPENDENT_EXPR. */
+ return build1 (NON_DEPENDENT_EXPR, TREE_TYPE (expr), expr);
}
/* ARGS is a vector of expressions as arguments to a function call.
new file mode 100644
@@ -0,0 +1,15 @@
+// { dg-options "-std=c++0x -pedantic-errors" }
+
+#include <utility>
+
+class A { };
+
+static void g ( A && ) { }
+
+template < class T > class B {
+public:
+ void f ( ) {
+ A a;
+ g ( std :: move ( a ) );
+ }
+};